[问答题]阅读以下说明,回答问题1~3,将解答填入对应栏内.(说明)某小公司的网络拓扑结构如图1-3所示.其中路由器具有ISDN模块,公司网络通过ISDN连接到ISP.在应用服务器关机的情况下,公司员工能连接上Internet吗?简要解释其原因.
[问答题](1)将数据库“school”添加到项目文件“xm”中.(2)将自由表“course”添加到数据库“school”中.(3)建立数据库表“course与表“score”之间的关联(两表的索引已经建立).(4)为(3)题中的两个表之间的联系设置完整性约束,要求:“更新”规则为“忽略”,“删除”规则和“插入”规则均为“限制”.
[问答题]中国共产党在民主革命中战胜敌人的三大法宝是什么
[问答题]若房地产供给的价格弹性大于1,房地产价格变化为1%,则房地产供给量的变化是
[问答题]在贯彻《劳动合同法》的过程中,为提高人力资源配置的效率,企业应在人力资源规划、招聘方面注意哪些问题
[问答题]写出TD-LTE分配的频段.
[问答题]某市建筑集团公司承担一栋20层智能化办公楼工程的施工总承包任务,层高3.3 m,其中智能化安装工程分包给某科技公司施工.在工程主体结构施工至第18层、填充墙施工至第8层时,该集团公司对项目经理部组织了一次工程质量、安全生产检查.部分检查情况如下.(1)现场安全标志设置部位有:现场出入口、办公室门口、安全通道151、施工电梯吊笼内;(2)杂工班外运的垃圾中混有废弃的有害垃圾;(3)第15层外脚手架上有工人在进行电焊作业,动火证是由电焊班组申请,项目责任工程师审批;(4)第5层砖墙砌体发现梁底位置出现水平裂缝;(5)科技公司工人在第3层后置埋件施工,打凿砖墙导致墙体开裂.问题:1.指出施工现场安全标志设置部位中的不妥之处.2.对施工现场有毒有害的废弃物应如何处置3.本案例,中电焊作业属几级动火作业?指出办理动火证的不妥之处,写出正确做法.4.分析墙体出现水平裂缝的原因并提出防治措施.5.针对打凿引起的墙体开裂事件,项目经理部应采取哪些纠正和预防措施
[问答题]人力资源师的考试要考哪些科目?报名的话可以以个人名义报吗
[问答题]如果张某在租赁期间将房屋卖给他人,承租人赵某是否可以要求以同等条件优先购买?并说明理由.
[问答题]利用(任务管理器)切换到文件“考试.doc”,然后关闭此文件,并注销当前用户.
[问答题](2)自薪辄诣县自代,而匿其兄他所 译:(2)自薪辄诣县自代,而匿其兄他所 译:
[问答题]是不是要考播音主持人资格证书或者记者证?需要什么参考书?怎么复习?需要报班么?谢谢~
[问答题]RRC过程主要包括
[问答题](c) Illustrate how:(i) inquiry; and (4 marks)
[问答题]从天安门到人大怎么走
[问答题]Moonstar Co is a property development company which is planning to undertake a $200 million commercial property development. Moonstar Co has had some difficulties over the last few years, with some developments not generating the expected returns and the company has at times struggled to pay its finance costs. As a result Moonstar Co’s credit rating has been lowered, affecting the terms it can obtain for bank finance. Although Moonstar Co is listed on its local stock exchange, 75% of the share capital is held by members of the family who founded the company. The family members who are shareholders do not wish to subscribe for a rights issue and are unwilling to dilute their control over the company by authorising a new issue of equity shares. Moonstar Co’s board is therefore considering other methods of financing the development, which the directors believe will generate higher returns than other recent investments, as the country where Moonstar Co is based appears to be emerging from recession.Securitisation proposalsOne of the non-executive directors of Moonstar Co has proposed that it should raise funds by means of a securitisation process, transferring the rights to the rental income from the commercial property development to a special purpose vehicle. Her proposals assume that the leases will generate an income of 11% per annum to Moonstar Co over a ten-year period. She proposes that Moonstar Co should use 90% of the value of the investment for a collateralised loan obligation which should be structured as follows:– 60% of the collateral value to support a tranche of A-rated floating rate loan notes offering investors LIBOR plus 150 basis points– 15% of the collateral value to support a tranche of B-rated fixed rate loan notes offering investors 12%– 15% of the collateral value to support a tranche of C-rated fixed rate loan notes offering investors 13%– 10% of the collateral value to support a tranche as subordinated certificates, with the return being the excess of receipts over payments from the securitisation processThe non-executive director believes that there will be sufficient demand for all tranches of the loan notes from investors. Investors will expect that the income stream from the development to be low risk, as they will expect the property market to improve with the recession coming to an end and enough potential lessees to be attracted by the new development.The non-executive director predicts that there would be annual costs of $200,000 in administering the loan. She acknowledges that there would be interest rate risks associated with the proposal, and proposes a fixed for variable interest rate swap on the A-rated floating rate notes, exchanging LIBOR for 9·5%.However the finance director believes that the prediction of the income from the development that the non-executive director has made is over-optimistic. He believes that it is most likely that the total value of the rental income will be 5% lower than the non-executive director has forecast. He believes that there is some risk that the returns could be so low as to jeopardise the income for the C-rated fixed rate loan note holders.Islamic financeMoonstar Co’s chief executive has wondered whether Sukuk finance would be a better way of funding the development than the securitisation.Moonstar Co’s chairman has pointed out that a major bank in the country where Moonstar Co is located has begun to offer a range of Islamic financial products. The chairman has suggested that a Mudaraba contract would be the most appropriate method of providing the funds required for the investment.Required:(a) Calculate the amounts in $ which each of the tranches can expect to receive from the securitisation arrangement proposed by the non-executive director and discuss how the variability in rental income affects the returns from the securitisation. (11 marks)(b) Discuss the benefits and risks for Moonstar Co associated with the securitisation arrangement that the non-executive director has proposed. (6 marks)(c) (i) Discuss the suitability of Sukuk finance to fund the investment, including an assessment of its appeal to potential investors. (4 marks)(ii) Discuss whether a Mudaraba contract would be an appropriate method of financing the investment and discuss why the bank may have concerns about providing finance by this method. (4 marks)
[问答题]食品添加剂的定义是什么?常见的食品添加剂是如何分类的
[问答题](2)对应于第2级暗纹中心,单缝波面被分为几个半波带
[问答题]基站如何知道终端的支持能力
[问答题]关系代数中的操作有哪些
[问答题]已知数据文件in.dat中存有300个四位数,并已调用读函数readDat把这些数存入数组a中,请编制一函数isValue,其功能是:求出所有这些四位数是素数的个数cnt,再把所有满足此条件的四位数依次存入数组b中,然后对数组b的四位数按从小到大的顺序进行排序.最后main函数调用写函数writeDat把数组b中的数输出到out.dat文件中. 例如:5591是素数,则该数满足条件存入数组b中,且个数cnt=cnt+1. 9812是非素数,则该数不满足条件忽略. 注意:部分源程序存在test.C文件中. 程序中已定义数组:a[300],b[300],已定义变量:cnt请勿改动数据文件in.dat中的任何数据、主函数main、读函数readDat和写函数writeDat的内容.! include< stdio.h>// include语句说明各程序中包含v60中的标准输入输出库函数 stdio hinta3001,b300,cnt=0;//定义全局数组a[3001,b13001和变量cnt,并且对变量cnt赋初值void readDat( )://函数 readOut( )说明语句oid writeDat( )://函数 writeDat( )说明语句void disvalue( );//函数 devalue( )说明语句int isp(intm)//函数⊥sP(m)判断m是否为素数,如果是素数,返回1,否则返回0inti;//定义变量1for(⊥=2;f<m:i++)/循环变量i从2依次递增,直到⊥等于或大于m退出循环if(m1==0)return0;//如果m能被1整除,返回0retUvoid main( )inti://定义变量11: redhat( ):/调用 ceadDa( )函数从数据文件 in, dat中读取300个四位数存入数组a中2 svalue( );//调用函数 svalue)实现题目所要求的功能3! writeDat( );//调用 writeDat( )函数把计算结果写入到数组b中的数输出到 out dat文件24 printf(\cnt=8d\\n\,cnt);//在屏幕上显示素数的个数25: for(i =0: i< cnt: 1++)printf(\b[d]=8dn\,i,b[i]);//在屏幕上显示数组b中的所有元素28: void readDat( )0FILE\fp;/定义文件指针变量rp31!int1;//定义整型变量132fp= fopen(\in,dat\,\r\);/以只读的方式打开文件in,dat,并用p指向这个文件33for(⊥=0:1<300:1++)34fscanf(fp,\td,\,a[11)://从文件1n,dat中读取300个四位数到数组a中35} fclose(tp);∥关闭文件in,dt36!37 i void writeDat ( )39!FILE·fp;//定义文件指针变量fp40 L int i;//定义整型变量41 tp fopen(\out.dat\,\w\);∥/以只写的方式打开文件out,dat,并用印p指向这个文件42! fprintf(fp,\sd\\n\,cnt);/把素数的个数写入到文件out.dat43:for(⊥0:i<cnt:⊥++)fprintf(fp,\8dn\,bi1);//把数组b中的所有元素写入到文件out,dat45 fclose(fp);/关闭文件out,dat